Find the surface area of a rectangular parallelepiped whose length and width are 6 cm and height

Find the surface area of a rectangular parallelepiped whose length and width are 6 cm and height 3 cm. Find the sum of all its edges.

Let’s find the surface area of a rectangular parallelepiped, which is equal to twice the sum of the areas of its faces:

S = 2 (6 * 6 + 6 * 3 + 3 * 6) = 2 (36 + 18 + 18) = 2 * 72 = 144 (cm²).

Let’s find the sum of all the edges of a rectangular parallelepiped if its three dimensions are 6 cm, 6 cm and 3 cm, which is found by multiplying the sum of three dimensions by 4:

L = 4 (6 + 6 + 3) = 4 * 15 = 60 (cm).

Answer: the surface area of a rectangular parallelepiped is 144 cm², the sum of the lengths of all edges is 60 cm.