Find the surface area of a rectangular parallelepiped whose volume is 6 dm3, the length and width are 2 dm

Find the surface area of a rectangular parallelepiped whose volume is 6 dm3, the length and width are 2 dm and 1 dm, respectively.

Let us find the area of all faces of a rectangular parallelepiped, provided that its volume is 6 dm³, length = 2 dm, and width = 1 dm.

First of all, it is necessary to calculate the height of such a figure, expressing it from the formula to determine the volume.

If V = a * b * c, therefore, the unknown factor is the quotient of the other two:

c = V: b: a = 6: 1: 2 = 3 dm.

The formula for calculating the total surface area is:

S = 2 * (ab + bc + ac).

Substitute the known values and write the expression:

S = 2 * (2 * 1 + 1 * 3 + 2 * 3) = 2 * 11 = 22 dm².