Find the surface area of the parallelepiped if the height is 3 cm, the length is 11 and the width is 5 cm.

A box is a three-dimensional shape. Hence, its surface area consists of the sum of the areas of all its faces. The box has three pairs of equal faces. These faces are opposite each other. The sides of such faces are:

1) Height and length.

2) Height and width.

3) Length and width.

Each face is a rectangle. This means that the formula for the area of ​​one face is:

Sgr = a * b,

where a, b are the sides of the rectangle.

Find the areas of different faces:

1) Sgr1 = 3 * 11 = 33 cm2.

2) Sgr2 = 3 * 5 = 15 cm2.

3) Sgr3 = 11 * 5 = 55 cm2.

We found the areas of three different faces. Now we need to sum them up and multiply them by 2. This will give us the area of ​​the entire surface of the parallelepiped.

We get:

S = (Sgr1 + Sgr2 + Sgr3) * 2;

S = (33 + 15 + 55) * 2;

S = 103 * 2;

S = 206 cm2.

Answer: 206 cm2.