Find the total body surface area obtained by rotating a 12m and 5m rectangle around the smaller side?

When the rectangle rotates around its side, a cylinder is formed. The height, in this case, will be 5 m, and the radius is 12 m.

The complete cylinder surface consists of a lateral surface and two bases:

Sp.p. = Sb.p. + 2 S main;

Let’s find the lateral surface area:

Sb.p. = 2πrh;

Sb.p. = 2 · 3.14 · 12 · 5 = 376.8 m2;

Now we are looking for the base area:

Sbas. = Πr ^ 2;

Sb. = 3.14 * 12 ^ 2 = 3.14 * 144 = 452.16 m2;

Sp.p. = 376.8 + 2 · 452.16 = 1281.12 m2.

Answer: the total surface area of this body is 1281.12 m2.