Find the total resistance of the circuit in parallel connection, if R1 = 20Om. R2 = 30Om. R3 = 10Om

Given:

R1 = 20 Ohm – first resistance;

R2 = 30 Ohm – second resistance;

R3 = 10 Ohm – third resistance.

It is required to determine the total resistance of the section of the electrical circuit R (Ohm).

Since, according to the condition of the problem, the resistances are connected in parallel, then:

1 / R = 1 / R1 + 1 / R2 + 1 / R3;

1 / R = (R2 * R3 + R1 * R3 + R1 * R2) / (R1 * R2 * R3);

R = (R1 * R2 * R3) / (R2 * R3 + R1 * R3 + R1 * R2) = (20 * 30 * 10) / (30 * 10 + 20 * 10 + 20 * 30) = 6000 / (300 + 200 + 600) = 6000/1100 = 5.45 Ohm.

Answer: The total resistance of the circuit is 5.45 ohms.