Find the value of the acute angle of the parallelogram ABCD, if the bisector of angle A

Find the value of the acute angle of the parallelogram ABCD, if the bisector of angle A makes an angle = 33 degrees with the side BC?

1. It is known that AK – the bisector of the angle A makes an angle of 33 degrees with the side BC. In turn, the bisector is a secant of two parallel lines AD and BC, therefore:

∠AKB = ∠KAD = 33 °;

2. Hence, sharp ∠A = 33 ° * 2 = 66 °;

3. Answer: acute ∠A = 66 °.