Find the values of the function f (x) = 3x ^ 2 + 2x-1 at the points -1; 0; 0.5

In order to find the value of the function f (x) = 3 * x ^ 2 + 2 * x – 1 in points, you need to substitute the values of the points instead of x into the function and calculate its expression.

1) f (-1) = 3 * (-1) ^ 2 + 2 * (-1) – 1 = 3 * 1 – 2 * 1 – 1 = 3 – 2 – 1 = 1 – 1 = 0;

2) f (0) = 3 * 0 ^ 2 + 2 * 0 – 1 = 3 * 0 + 2 * 0 – 1 = 0 + 0 – 1 = -1;

3) f (0.5) = 3 * 0.5 ^ 2 + 2 * 0.5 – 1 = 3 * 0.25 + 2 * 1/2 – 1 = 3 * 3/4 + 1 – 1 = 9 / 4 + 0 = 2 + 0.25 = 2.25.