Find the voltage at which the light is on. The strength of the current in the spiral of the light bulb is 0.8 A
| May 13, 2021 | education
Find the voltage at which the light is on. The strength of the current in the spiral of the light bulb is 0.8 A. The resistance of the spiral in the heated state is 275 ohms.
To find out the voltage at which the taken light bulb should burn, we apply Ohm’s law (we consider the section of the circuit): U = I * R, where I is the current in the spiral (I = 0.8 A); R is the resistance of the spiral of the taken light bulb in the heated state (R = 275 Ohm).
Calculation: U = I * R = 0.8 * 275 = 220 V.
Answer: The taken light bulb should burn at a voltage of 220 V.
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