Find the volume and number of molecules for 132 kg of carbon monoxide (IV).

Given:
m (CO2) = 132 kg
Vm = 22.4 l / mol
Na = 6.02 · 10²³ mol-1
To find:
V (CO₂) -?
N (CO₂) -?

Decision:

1. Find the molar mass of carbon monoxide (lV):
M (CO₂) = 12 + 16×2 = 44 g / mol = 0.044 kg / mol
2. Find the amount of substance n in 132 kg of carbon monoxide (lV) by the formula:
n = m ÷ M n (CO₂) = 132 kg ÷ 0.044 kg / mol = 3000 mol = 3 kmol
3. Find the volume of carbon monoxide (lV) with the amount of substance 3 kmol by the formula:
V = Vm × n V (CO₂) = 22.4 L / mol x 3 kmol = 67.2 L
4. Find the number of molecules in 3 kmol of carbon monoxide (lV) by the formula: ·
N = n x Na N (CO₂) = 3 kmol x 6.02 · 10²³ mol-1 = 18.06 · 10²⁶ molecules.