Find the volume of 70 kg of carbon monoxide (II)

To find out the volume occupied by the taken carbon monoxide (CO), consider the equality: m / MCO = ν (amount of substance) = V / Vm, whence we can express: V = Vm * m / MCO.

Const: Vm – molar volume (Vm = 22.4 l / mol); MCO is the molar mass of carbon monoxide (MCO ≈ 28 g / mol).

Data: m is the mass of carbon monoxide (MCO = 70 kg).

Let’s calculate: V = Vm * m / MCO = 22.4 * 70/28 = 56 liters.

Answer: Carbon monoxide (CO) weighing 70 kg should occupy a volume of 56 liters.



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