Find the volume of 80% nitric acid solution (p = 1.45 g / ml) required to obtain trinitroglycerin from 69 g of glycerin.

| February 19, 2021 | education

1. Getting trinitroglycerin occurs according to the reaction equation:

CH2 (OH) CH (OH) CH2 (OH) + 3HNO3 → CH2 (ONO2) CH (ONO2) CH2 (ONO2) + 3H2O;

2.Calculate the chemical amount of glycerin:

n (glycerol) = m (glycerol): M (glycerol);

M (glycerol) = 14 +17 + 13 + 17 + 14 + 17 = 92 g / mol;

n (glycein) = 69: 92 = 0.75 mol;

3. Determine the amount of nitric acid that went into the reaction:

n (HNO3) = n (glycerol) * 3 = 0.75 * 3 = 2.25 mol;

4.calculate the mass of the acid:

m (HNO3) = n (HNO3) * M (HNO3);

M (HNO3) = 1 + 14 + 3 * 16 = 63 g / mol;

m (HNO3) = 2.25 * 63 = 141.75 g;

5.Set the mass of the nitric acid solution:

m (solution HNO3) = m (HNO3): w (HNO3) = 141.75: 0.8 = 177.1875 g;

6. find the volume of the acid solution:

V (solution HNO3) = m (solution HNO3): ρ = 177.1875: 1.45 = 256.9 ml.

Answer: 256.9 ml.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.