Find the volume of a cylinder if the base radius is 4.6 cm and the axial section is 6.8 cm2

Given: where the base radius is BF = 4.6 cm and the axial section area is 6.8 cm². It is necessary to find the volume (V) of the cylinder.
As you know, the volume (V) of a cylinder is calculated by the formula V = π * R2 * H, where R is the radius of the base of the cylinder, H is the height of the cylinder.
The radius of the base of the cylinder is R = BF = 4.6 cm, which means that you must first find the height of the cylinder, which is equal to H = AB the height of the rectangle ABCD (the axial section of the cylinder).
Let’s use the formula for determining the area of ​​a rectangle S = a * b, where a and b are the sides of the rectangle.
It is clear that BC is the diameter of the cylinder: BC = 2 * R = 2 * BF = 2 * 4.6 cm = 9.2 cm.
So, S = AB * BC = H * 9.2 cm = 6.8 cm², whence H = (6.8 cm²): (9.2 cm) = 17/23 cm.
Thus, V = π * (4.6 cm) 2 * (17/23 cm) = π * (21.16 * 17/23) cm3 = 15.64 * π cm3.
Answer: The volume of the cylinder is 15.64 * π cm3.



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