Find the volume of a rectangular parallelepiped whose length is seven-eighths of a meter

Find the volume of a rectangular parallelepiped whose length is seven-eighths of a meter, the width is three-eighths less than the length, and the height is 6 times the width.

1. Let’s find out the width of the parallelepiped, if it is 3/8 meters less than its length, we get:
7/8 – 3/8 = 4/8 m = 1/2 m.
2. Now let’s calculate the value of the height of the parallelepiped, if it is 6 times the width, we get:
6 * 1/2 m = 3 m.
3. Finally, let’s find out the value of the volume of the parallelepiped, as the product of height, width and length, we get the following expression:
Volume = 7/8 * 1/2 * 3 = 7/16 * 3 = 21/16 m3 = 1 ^ 5/16 m3.
Answer: as a result of calculations, a volume equal to 1 ^ 5/16 m3 was obtained.