Find the volume of a triangular pyramid, the sides of the base of which are 5 cm, 5 cm, 6 cm, the height is 12 cm

h (sabc) bases = sabc (5 ^ 2 – (6/2) ^ 2) = 4 (cm);
S (sabc) bases = 6 * 4/2 = 12 (cm);
V (sabc) = 1/3 * (6 * 4/2) * 12 = 48 (cm ^ 3);
Answer: 48 cm ^ 3.

 



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