Find the volume of air to burn 60 g of silicon.
| February 19, 2021 | education
Si + O2 = SiO2.
Silicon reacted:
60 g: 28 g / mol = 15/7 mol, the same amount of oxygen will be required, or 15/7 mol * 22.4 L / mol = 48 L.
Considering that the oxygen content in the air mixture is 21%, air for the reaction will be needed: 48 * (100%: 21%) = 228.57 liters.
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