Find the volume of ammonia that will be released when 0.4 g of sodium hydroxide interacts with ammonium chloride.

This reaction proceeds according to the following chemical reaction equation:

2NH4Cl + Ca (OH) 2 = 2NH3 + CaCl2; + 2H2O;

Let’s determine the chemical amount of calcium hydroxide. To do this, we divide its weight by its molar mass.

M Ca (OH) 2 = 40 + 17 x 2 = 74 grams / mol;

The amount of calcium oxide will be:

N Ca (OH) 2 = 0.4 / 74 = 0.0054 mol;

With 0.0054 mol of ammonium chloride, 0.0054 / 2 = 0.0027 mol of calcium hydroxide will react. This will synthesize 0.0054 mol of ammonia.

Let’s calculate its volume.

To do this, multiply the amount of substance by the standard volume of 1 mole of gas (filling 22.40 liters)

V NH3 = 0.0054 x 22.4 = 0.121 liters;