Find the volume of carbon dioxide (CO2), which is formed during the combustion of acetylene weighing 5.2 g

Let’s implement the solution:

According to the condition of the problem, we compose the equation of the process:
2С2Н2 + 5О2 = 4СО2 + 2Н2О + Q – combustion of acetylene, heat, carbon dioxide, water are released;

Let’s make the calculations:
M (C2H2) = 26 g / mol;

M (CO2) = 44 g / mol;

Y (C2H2) = m / M = 5.2 / 26 = 0.2 mol.

Proportion:
0.2 mol (C2H2) – X mol (CO2);

-2 mol – 4 mol from here, X mol (CO2) = 0.2 * 4/2 = 0.4 mol.

Find the volume of the product:
V (CO2) = 0.4 * 22.4 = 8.96 L

Answer: received carbon monoxide (4) with a volume of 8.96 liters.