Find the volume of carbon dioxide generated by the action of a sulfuric acid solution on 180 g of marble containing 10% impurities.

Given:
m mixture (CaCO3) = 180 g
w approx (CaCO3) = 10%
To find:
V (CO2)
Decision:
CaCO3 + H2SO4 = H2O + CO2 + CaSO4
w is clean. islands (CaCO3) = 100% -10% = 90% = 0.9
m in islands (CaCO3) = w pure. in-va * m mixture = 0.9 * 180 g = 162 g
n (CaCO3) = m / M = 162 g / 100 g / mol = 1.62 mol
n (CaCO3): n (CO2) = 1: 1
n (CO2) = 1.62 mol
V (CO2) = n * Vm = 1.62 mol * 22.4 l / mol = 36.3 l
Answer: 36.3 l