Find the volume of carbon dioxide produced by the action of hydrochloric acid on 5 g

Find the volume of carbon dioxide produced by the action of hydrochloric acid on 5 g of limestone containing 15% of impurities.

The reaction of calcium carbonate with hydrochloric acid is described by the following chemical reaction equation:

CaCO3 + 2HCl = CaCl2 + CO2 + H2O;

One mole of limestone forms one mole of calcium chloride.

Let’s find the amount of limestone substance.

The mass of pure limestone will be:

m CaCO3 = 5 x 0.85 = 4.25 grams;

Its molar mass is:

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

The amount of the substance will be:

N CaCO3 = 4.25 / 100 = 0.0425 mol;

The same amount of carbon monoxide and calcium oxide will be obtained.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Let’s determine the volume of carbon dioxide:

V CO2 = 0.0425 x 22.4 = 0.952 liters;