Find the volume of carbon dioxide released during the interaction of nitric acid with marble weighing 60 g

Find the volume of carbon dioxide released during the interaction of nitric acid with marble weighing 60 g and containing 25% impurity.

To solve the problem, we compose the equation of the process:

CaCO3 + 2HNO3 = Ca (NO3) 2 + H2O + CO2 – ion exchange, carbon dioxide is released;
Calculations by the formulas of substances:
M (CaCO3) = 100 g / mol;

M (CO2) = 44 g / mol:

m (CaCO3) = 60 * (1 – 0.25) = 45 g (mass without impurity).

Determine the amount of the original substance:

Y (CaCO3) = m / M = 45/100 = 0.45 mol;

Y (CO2) = 0.45 mol since the amount of substances according to the equation is 1 mol.

Find the volume of the product:

V (CO2) = 0.45 * 22.4 = 10.08 L

Answer: the volume of carbon dioxide is 10.08 liters