Find the volume of carbon dioxide that is formed during the decomposition of 315 grams of magnesium

Find the volume of carbon dioxide that is formed during the decomposition of 315 grams of magnesium carbonate containing 20% impurities.

The thermal decomposition reaction of magnesium carbonate when heated is described by the following chemical reaction equation:
MgCO3 = MgO + CO2 ↑;
Find the chemical amount of magnesium carbonate. To do this, we divide its weight by the mass of 1 mole of the substance.
M MgCO3 = 24 + 12 + 16 x 3 = 84 grams / mol;
N MgCO3 = 315 x 0.8 / 84 = 3 mol;
The same molar amount of carbon dioxide can theoretically be obtained.
In order to calculate its volume, you need to multiply the amount of substance by the volume of 1 mole of gas (taking a volume of 22.4 liters).
V CO2 = 3 x 22.4 = 67.2 liters.



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