Find the volume of carbon dioxide that is released during the combustion of decine (C10H18)

Find the volume of carbon dioxide that is released during the combustion of decine (C10H18), if 696 g of oxygen were consumed.

To solve the problem, we will compose an equation, select the coefficients:
2С10Н18 + 29О2 = 20СО2 + 18Н2О – decine combustion reaction, carbon dioxide and water are released;
Let’s make calculations using the formulas:
M (O2) = 32 g / mol;
Y (O2) = m / M = 696/32 = 21.75 mol.
Determine the amount of moles of carbon dioxide, make up the proportion:
21.75 mol (C10H18) – X mol (CO2);
– 29 mol – 20 mol from here, X mol (CO2) = 21.75 * 20/29 = 15 mol.
Let’s calculate the volume of carbon dioxide:
V (CO2) = 15 * 22.4 = 336 l.
Answer: the volume of carbon dioxide is 336 liters.