Find the volume of carbon dioxide, which is formed by the action of 73 g of 10%

Find the volume of carbon dioxide, which is formed by the action of 73 g of 10% hydrochloric acid solution on calcium carbonate.

Given:
m solution (HCl) = 73 g;
ω (HCl) = 10%;
V (CO2) -?
Solution:
We will use the formulas:
n = m in-va / M in – va.
V = n * VM.
Let’s write the reaction equation:
CaCO3 + 2HCl = CaCl2 + CO2 ↑ + H2O.
Let’s find the mass of the acid contained in the solution:
m (HCl) = 73 * 0.1 = 7.3 (g).
M (HCl) = 1 + 35.5 = 36.5 (g / mol).
n (HCl) = 7.3 / 36.5 = 0.2 (mol).
Given the ratio of the amount of substances in the equation, we get:
n (CO2) <n (HCl) 2 times, which means:
n (CO2) = 0.2 / 2 = 0.1 (mol).
Let’s find the volume of CO2:
V (CO2) = n (CO2) * VM = 0.1 * 22.4 = 2.24 (L).
Answer: The volume of CO2 is 2.24 liters.