Find the volume of carbon dioxide, which is formed when burning 60 g of coal.

Given:
m (C) = 60 g

Find:
V (CO2) -?

1) C + O2 => CO2;
2) M (C) = Ar (C) = 12 g / mol;
3) n (C) = m (C) / M (C) = 60/12 = 5 mol;
4) n (CO2) = n (C) = 5 mol;
5) V (CO2) = n (CO2) * Vm = 5 * 22.4 = 112 liters.

Answer: The CO2 volume is 112 liters.



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