Find the volume of carbon monoxide (IV), which will be released by the action of hydrochloric acid on 22 g

univerkov | December 1, 2020 | education

Find the volume of carbon monoxide (IV), which will be released by the action of hydrochloric acid on 22 g of limestone containing 5% non-carbonate impurities. Perform calculations with an accuracy of hundredths.

make an equation
CaCO₃ + 2HCl = CaCl₂ + CO₂ + H₂O
find mass
M (CaCO₃) = 300g x0.95 = 285g
then the amount of substance
n (CacCO₃) = 285g / 100g / mol = 2.85 mol (from equation)
V (CO₂) = 2.85 mol x 22.4 L / mol = 63.84 L
Answer 63.84L

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