1. Calculate the mass of acetic acid contained in the prepared solution:
m (CH3COOH) = w (CH3COOH) * m (solution) = 0.1 * 350 = 35 g.
2. Set the mass of water in the solution:
m (H2O) = m (solution) – m (CH3COOH) = 350 – 35 = 315 g.
3. Assuming that the density of water is 1 g / ml, we find the required volume of water:
V (H2O) = m (H2O): ρ (H2O) = 315: 1 = 315 ml.
Answer: 315 ml.
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