Find the volume of gas if 200 g of limestone has entered into the reaction with hydrochloric acid of which 20% impurity?

| March 20, 2021 | education

Let’s write the reaction equation:
CaCO3 + 2HCl = CaCl + H2O + CO2 ↑.
Determine the mass of pure calcium carbonate in limestone:
w (CaCo3) = 100-20 = 80%.
w (in-va) = (m (in-va) / m (solution)) * 100%.
Let us express the mass of a substance from this expression:
m (in-va) = (w (in-va) * m (solution)) / 100%.
m (CaCO3) = (w (CaCO3) * m (solution)) / 100%.
Let’s calculate:
m (CaCO3) = (w (CaCO3) * m (solution)) / 100% = 80 * 200/100 = 160 g.
From the reaction equation:
ν (CaСО3) = ν (СО2).
m (CaCO3) / M (CaCO3) = V (CO2) / Vm (CO2).
Vm (CO2) = 22.4 l / mol.
Let’s calculate the molar mass of calcium carbonate:
M (CaCO3) = 40 + 12 + 16 * 3 = 100 g / mol.
Let’s determine the volume of carbon dioxide:
V (CO2) = m (CaCO3) * Vm (CO2) / M (CaCO3).
Substitute the numerical values:
V (CO2) = 160 * 22.4 / 100 = 35.84 liters.
Answer: 35.84 liters of carbon dioxide will be released.



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