Find the volume of gas produced by the interaction of 900 grams of limestone.

The limestone decomposition reaction is described by the following chemical reaction equation:
CaCO3 = CaO + CO2;
The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.
Let’s calculate the available chemical amount of calcium carbonate substance.
M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;
N CaCO3 = 900/100 = 9 mol;
During the reaction, the same amount of carbon dioxide will be synthesized.
Let’s calculate its volume.
To do this, we multiply the amount of substance and the standard volume of 1 mole of gaseous substance.
1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.
V CO2 = 9 x 22.4 = 201.6 liters = 0.2 m3;