Find the volume of gas released by dissolving 38.8 zinc sulfide in excess sulfuric acid solution.

To solve, we write down the equation of the process:

ZnS + H2SO4 (dil.) = H2S + ZnSO4 – ion exchange, hydrogen sulfide is released;

Let’s make the calculations:
M (ZnS) = 97.3 g / mol;

M (H2S) = 34 g / mol.

Determine the amount of zinc sulfide:
Y (ZnS) = m / M = 38.8 / 97.3 = 0.398 mol;

Y (H2S) = 0.398 mol since the amount of these substances is 1 mol.

Find the volume of the product:
V (H2S) = 0.398 * 22.4 = 8.92 L

Answer: the volume of hydrogen sulfide is 8.92 liters.

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