Find the volume of gas released during the interaction of 27 g of hydrochloric acid with aluminum.

The reaction of dissolution of aluminum in hydrochloric acid is described by the following chemical reaction equation:

Al + 3HCl = AlCl3 + 3 / 2H2;

When 1 mol of metal is dissolved, 1.5 mol of hydrogen gas is synthesized.

Let’s calculate the amount of substance contained in 27 grams of acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 27 / 36.5 = 0.74 mol;

When reacting with this amount of acid, 0.74 / 2 = 0.37 mol of hydrogen gas will be released.

Let’s calculate its volume.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V H2 = 0.37 x 22.4 = 8.288 liters;