Find the volume of gas released during the interaction of 98 g of concentrated sulfuric acid with copper.

Let’s write the equation for solving the problem:
Cu + 2H2SO4 (conc.) = CuSO4 + SO2 + 2H2O – redox reaction, sulfur dioxide is released;
Let’s calculate the molar masses of substances:
M (H2SO4) = 98 g / mol;
M (SO2) = 64 g / mol.
Determine the amount of moles of sulfuric acid:
Y (H2SO4) = m / M = 98/98 = 1 mol.
Let’s make the proportion:
1 mol (H2SO4) – X mol (SO2)
-2 mol – 1 mol from here, X mol (SO2) = 1 * 1/2 = 0.5 mol.
Let’s calculate the volume of sulfur oxide:
V (SO2) = 0.5 * 22.4 = 11.2 liters.
Answer: the volume of sulfur dioxide is 11.2 liters.