Find the volume of gas that was formed by the interaction of 47 grams of magnesium with sulfuric acid.

We draw up the reaction equation and place the coefficients: Mg + H2SO4 = MgSO4 + H2.
1) According to the periodic table, we find the molar mass of magnesium: 24.
2) Find the amount of magnesium substance. To do this, divide its mass by the molar mass: 47/24 = 1.96 mol.
3) According to the reaction equation, there is one mole of hydrogen for one mole of magnesium. This means that the amount of hydrogen substance is 1.96 mol.
4) Find the volume of hydrogen. To do this, we multiply the amount of hydrogen substance by the molar volume: 1.96 * 22.4 = 43.9 liters – the answer.