# Find the volume of gas that will be released when zinc interacts with 180 g of a solution

Find the volume of gas that will be released when zinc interacts with 180 g of a solution of dilute sulfuric acid with a mass fraction of 20%.

Zinc metal reacts with sulfuric acid to release hydrogen gas and form zinc sulfate. The reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

1 mole of metal reacts with 1 mole of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 180 x 0.2 / 98 = 0.367 mol;

During the reaction, 0.367 mol of hydrogen will be synthesized. Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas.

V H2 = 0.367 x 22.4 = 8.221 liters;

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