Find the volume of H2 that will be released when a 9gr solution of 10% sulfuric acid interacts with magnesium.

| March 5, 2021 | education

1.Let’s find the mass of acid in the solution.

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (9 g × 10%): 100% = 0.9 g.

2.Let’s find the amount of sulfuric acid substance by the formula:

n = m: M.

M (H2SO4) = 98 g / mol.

n = 0.9 g: 98 g / mol = 0.009 mol.

3. Let’s compose the reaction equation, find the quantitative ratios of substances.

Mg + H2SO4 = MgSO4 + H2.

According to the reaction equation, there is 1 mole of hydrogen per mole of acid. Substances are in quantitative ratios 1: 1.

The amount of substance will be the same.

n (H2SO4) = n (Mg) = 0.009 mol.

4.Let’s find the volume of oxygen

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 22.4 L / mol × 0.009 mol = 0.2 L.

Answer: V = 0.2 l.



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