Find the volume of hydrogen gas that is formed during the decomposition of 64 grams of methane.

1. Let’s compose the equation:
2CH4 = C2H2 + 3H2 – the reaction of decomposition, cracking of methane leads to the formation of gaseous hydrogen, acetylene;
2. Determine the number of moles of methane, if its mass is known: m (CH4) = 64 g;
M (CH4) = 12 + 4 = 16 g / mol; Y (CH4) = m (CH4) / M (CH4); Y (CH4) = 64/16 = 4 mol;
3. Let’s make the proportion:
4 mol (CH4) – X mol (H2);
-2 mol -3 mol from here, X mol (H2) = 4 * 3/2 = 6 mol;
4. Let’s calculate the volume of hydrogen according to Avogadro’s law:
V (H2) = 6 * 22.4 = 134.4 liters.
Answer: during the decomposition of methane, hydrogen was released with a volume of 134.4 liters.