Find the volume of hydrogen gas that will be released during the reaction of 300 g of aluminum with hydrochloric acid.

Aluminum reacts violently with hydrochloric acid. At the same time, the salt of aluminum chloride is synthesized and bubbles of hydrogen gas are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s calculate the chemical amount of aluminum. To do this, divide its weight by the weight of 1 mole of the substance.

M Al = 27 grams / mol;

N Al = 300/27 = 11.111 mol;

This will synthesize the same amount of salt.

The chemical amount of released hydrogen will be: 11.111 x 3/2 = 16.666 mol

Let’s define its volume.

For this purpose, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 16.666 x 22.4 = 373.33 liters;