Find the volume of hydrogen H2 in the interaction of 03, mole of zinc Zn with hydrochloric acid HCl.

When dissolved in hydrochloric acid, metallic zinc is converted to zinc chloride.

Zn + 2HCl = ZnCl2 + H2;

We have 0.3 mol of metallic zinc.

With this amount of zinc, 0.3 x 2 = 0.6 mol of acid reacts.

This will synthesize 0.3 mol of hydrogen and 0.3 mol of zinc chloride.

Let’s determine the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V H2 = 0.3 x 22.4 = 6.72 liters;