Find the volume of hydrogen if zinc reacts with 146 g of hydrochloric acid containing 25% of impurities.

Zinc metal reacts with hydrochloric (hydrochloric) acid to release hydrogen gas and form zinc chloride. The reaction is described by the following equation:

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the available chemical amount of acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 146 x 0.75 / 36.5 = 3 mol;

Half the amount of hydrogen will be synthesized. Let’s calculate its volume.

To do this, we divide its volume by the volume of 1 mole of ideal gas, which is 22.4 liters.

N H2 = 3/2 = 1.5 mol;

V H2 = 1.5 x 22.4 = 33.6 liters;