Find the volume of hydrogen (L) that will be released when dissolving 16.8 g of iron in an excess

Find the volume of hydrogen (L) that will be released when dissolving 16.8 g of iron in an excess of dilute hydrochloric acid (HCl)?

To solve, we compose the equation of the process:

m = 16.8 g X l -?

Fe + 2HCl = FeCl2 + H2 – OBP, hydrogen is evolved;

We make calculations:
M (Fe) = 55.8 g / mol;

M (H2) = 2 g / mol.

Determine the amount of the original substance, if the mass is known:
Y (Fe) = m / M = 16.8 / 55.8 = 0.3 mol;

Y (H2) = 0.3 mol since the amount of substances is 1 mol.

Find the volume of the product:
V (H2) = 0.3 * 22.4 = 6.72 L

Answer: hydrogen produced with a volume of 6.72 liters