Find the volume of hydrogen needed to hydrogenate 330 g of ethanal.

To solve the problem, let’s compose the reaction equation, arrange the coefficients:
CH3 – COH + H2 = CH3 – CH2 – OH – addition reaction, ethanol was obtained;
M (C2H4O) = 44 g / mol;
M (H2) = 2 g / mol;
Determine the number of moles of ethanal by the formula:
Y (C2H4O) = m / M = 330/44 = 7.5 mol;
According to the equation, we make up the proportion:
7.5 mol (C2H4O) – X mol (H2);
-1 mol -1 mol hence, X mol (H2) = 7.5 * 1/1 = 7.5 mol;
Let’s calculate the volume of hydrogen:
V (H2) = 7.5 * 22.4 = 168 HP
Answer: the reaction will require 168 liters of hydrogen.