# Find the volume of hydrogen released by the interaction of 3.9 g of potassium with hydrobromic acid.

August 27, 2021 | education

| Let’s write down the reaction equation, arrange the coefficients:

2K + 2HBr = 2KBr + H2 – redox reaction, hydrogen is released;

M (K) = 39.1 g / mol;

M (H2) = 2 g / mol;

Determine the amount of potassium moles if the mass is known:

Y (K) = m / M = 3.9 / 39 = 0.09 mol;

Let’s make a proportion according to the equation:

0.09 mol (K) – X mol (H2);

-2 mol -1 mol hence, X mol (H2) = 0.09 * 1/2 = 0.049 mol;

Let’s calculate the volume of hydrogen:

V (H2) = 0.049 * 22.4 = 1.09 liters.

Answer: during the reaction, 1.09 liters of hydrogen is released.

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