Find the volume of hydrogen released during the interaction of 2.5 mol of Mg with an Hcl solution.
| September 21, 2021 | education
Given:
n (Mg) 2.5 mol.
Find the volume V (H2) -?
Solution :
Mg + 2HCl = MgCl2 + H2 ↑.
For 1 mole of Mg, there is 1 mole of H2.
Substances are in quantitative ratios 1: 1.
n (Mg) = n (H2) = 2.5 mol
V = Vn n.
V = 2.5 mol × 22.4 L / mol = 56 L.
Answer: 56 l.
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