Find the volume of hydrogen released during the interaction of ethanol 9.2 g and sodium weighing 5 g.

| November 28, 2020 | education

Find the volume of hydrogen released during the interaction of ethanol 9.2 g and sodium weighing 5 g. 2С2Н5ОН + 2Na = 2C2H5ONa + Н2.

2C2H5OH + 2Na = 2C2H5ONa + H2
1.Let’s find the amount of substance by the formula n = m / M, where n is the amount of the substance, m is the mass of the substance, M is the molar mass of the substance
n (C2H5OH) = 9.2 / 46 = 0.2 mol
n (Na) = 5/23 = 0.217 mol
Because there is a lack of ethanol, then further calculations are carried out on it
2.Using the reaction equation, we find n (H2)
The quantities of substances are also referred to as their coefficients
n (H2) = n (C2H5OH) / 2
n (H2) = 0.2 / 2 = 0.1 mol
3. The volume of hydrogen is found by the formula V = Vm × n, where V is the volume of gas, Vm is the molar volume of gas (22.4 l / mol), n is the amount of substance
V (H2) = 22.4 × 0.1 = 2.24 L
Answer: V (H2) = 2.24L



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