Find the volume of hydrogen required to react with 32 g of oxygen.

1. Let’s write down the reaction equation:

2H2 + O2 = 2H2O;

2.Calculate the chemical amount of oxygen spent on the reaction:

n (O2) = m (O2): M (O2) = 32: 32 = 1 mol;

3. according to the equation, there is one oxygen molecule for two hydrogen molecules, we find the amount of hydrogen:

n (H2) = n (O2) * 2 = 1 * 2 = 2 mol;

4.calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 2 * 22.4 = 44.8 liters.

Answer: 44.8 liters.