Find the volume of hydrogen that is released by the interaction of 6 g of magnesium with phosphoric acid.

Magnesium dissolves in phosphoric acid solution. The reaction is described by the following chemical equation:

3Mg + 2H3PO4 = Mg3 (PO4) 2 + 3H2 ↑;

Let’s calculate the chemical amount of magnesium.

For this purpose, we divide its weight by the weight of 1 mole of metallic magnesium.

M Mg = 24 grams / mol;

N Mg = 6/24 = 0.25 mol;

The same amount of hydrogen gas will be produced.

Let’s find the volume of hydrogen.

To do this, multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V H2 = 0.25 x 22.4 = 5.6 liters;