Find the volume of hydrogen that is released when 10.95 g of hydrochloric acid interacts with zinc.

Zinc metal reacts with hydrochloric (hydrochloric) acid to release hydrogen gas and form zinc chloride. The reaction is described by the following equation:
Zn + 2HCl = ZnCl2 + H2;
1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.
Let’s calculate the available chemical amount of acid.
M HCl = 1 + 35.5 = 36.5 grams / mol;
N HCl = 10.95 / 36.5 = 0.3 mol;
Half the amount of hydrogen will be synthesized. Let’s calculate its volume.
To do this, we divide its volume by the volume of 1 mole of ideal gas, which is 22.4 liters.
N H2 = 0.3 / 2 = 0.15 mol;
V H2 = 0.15 x 22.4 = 3.36 liters.