Find the volume of hydrogen that will be released in the substitution reaction between hydrochloric acid and aluminum

Find the volume of hydrogen that will be released in the substitution reaction between hydrochloric acid and aluminum, if 36 g of aluminum are taken, and hydrochloric acid is in excess.

1. Interaction proceeds according to the equation:

2Al + 6HCl = 2AlCl3 + 3H2 ↑;

2.Calculate the chemical amount of aluminum:

n (Al) = m (Al): M (Al) = 36: 27 = 1.33 mol;

3.determine the amount of hydrogen:

n (H2) = 3 * n (Al): 2 = 3 * 1.33: 2 = 1.995 mol;

4. find the volume of evolved hydrogen:

V (H2) = n (H2) * Vm = 1.995 * 22.4 = 44.688 dm3.

Answer: 44.688 dm3.