Find the volume of hydrogen that will be released when a 200 g solution of chloride acid with

Find the volume of hydrogen that will be released when a 200 g solution of chloride acid with an acid mass fraction of 1.825% reacts with zinc.

Under laboratory conditions, hydrogen is obtained by dissolving metallic zinc in hydrochloric acid.

Zn + 2HCl → ZnCl2 + H2;

The molar amount of hydrogen will be half the amount of hydrochloric acid reacted. This is due to the coefficients of the chemical equation.

Let’s calculate the chemical amount of hydrochloric acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 200 x 0.01825 / 36.5 = 0.1 mol;

Let us determine the volume of 0.1 / 2 = 0.05 mol of hydrogen.

V H2 = 22.4 x 0.05 = 1.12 liters;



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