Find the volume of hydrogen that will be released when dissolving with sulfuric acid (dilution) 65 g

Find the volume of hydrogen that will be released when dissolving with sulfuric acid (dilution) 65 g of zinc containing 10% impurity.

Zinc metal reacts with sulfuric acid to release hydrogen gas and form zinc sulfate. The reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

1 mole of metal reacts with 1 mole of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the amount of zinc.

M Zn = 65 grams / mol;

N Zn = 65 x 0.9 / 65 = 0.9 mol;

During the reaction, 0.9 mol of hydrogen will be synthesized. Let’s calculate its volume.

To do this, we multiply the amount of substance by the volume of 1 mole of gas.

V H2 = 0.9 x 22.4 = 20.16 liters;