Find the volume of hydrogen under normal conditions required to obtain an alkane from 81 g of butadiene-1,3.

univerkov | December 10, 2020 | education

butadiene 1 3: С4H6
n (butadiene) = 81 / (12 * 4 + 6) = 1.5 mol
C4H6 + 2H2 = C4H10
n (H2) = 1.5 * 2 = 3 mol
v (H2) = 3 * 22.4 = 67.2 liters
answer 67.2 liters

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